Question

4( х- 1)= 2 (2х- 8 )+12

Answer 1

$4(x - 1) = 2(2x - 8) + 12 \\ 4x - 4x = 12 - 16 + 4 = \\ 0 = 0$

Это равенство верно при любом х

Answer 2

4х-4=4х-16+12

4х-4х=-16+12+4

0=0 при любом х

Уравнение имеет множество решений.

Answer 3

Let's solve the given equation step by step:

4(x - 1) = 2(2x - 8) + 12

First, let's simplify the equation:

4x - 4 = 4x - 16 + 12

Next, combine like terms:

4x - 4 = 4x - 4

Now, notice that the variable "x" appears on both sides of the equation. In this case, the equation is called an identity because it holds true for all values of "x". This means that the solution to the equation is any real number.

In conclusion, the equation 4(x - 1) = 2(2x - 8) + 12 is an identity, and its solution is all real numbers.