Question

5y+7(3-y)=3(5-2y)-6-это первый. 7y-4(3y+5)=2-3(4y-9)

Answer 1

5y+7(3-y)=3(5-2y)-6

5y+21-7y=15-6y-6

5y-7y+6y=15-6-21

4y= -12

y=-12:4

у= - 3

 

 

7у-4(3у+5)=2-3(4у-9)

7у-12у-20=2-12у+27 

 7у-12у+12у=20+2+27

7у= 49

у=49:7

у=7 

 

 

Answer 2

$5y+7(3-y)=3(5-2y)-6$

 

$5y+21-7y=15-6y-6$

 

$21-2y=9-6y$

 

$6y-2y=9-21$

 

$4y=-12$

 

$y=-12:4$

 

$y=-3$

________________________________________________________________

$5\cdot(-3)+7\cdot(3-(-3))=3\cdot(5-2\cdot(-3))-6$ (это проверка)

 

$-15+7\cdot(3+3)=3(5+6)-6$

 

$-15+7\cdot6=3\cdot11-6$

 

$-15+42=33-6$

 

$27=27$

=============================================================

$7y-4(3y+5)=2-3(4y-9)$

 

$7y-12y-20=2-12y+27$

 

$-5y-20=29-12y$

 

$12y-5y=29+20$

 

$7y=49$

 

$y=49:7$

 

$y=7$

___________________________________________________________

$7\cdot7-4\cdot(3\cdot7+5)=2-3\cdot(4\cdot7-9)$

 

$49-4\cdot(21+5)=2-3\cdot(28-9)$

 

$49-4\cdot26=2-3\cdot19$

 

$49-104=2-57$

 

$-55=-55$

Answer 3

Let's solve each equation step by step:

1. 5y + 7(3-y) = 3(5-2y) - 6

Expanding the brackets, we get:

5y + 21 - 7y = 15 - 6y - 6

Simplifying both sides of the equation, we get:

-2y + 21 = 9 - 6y

Adding 6y to both sides of the equation, we get:

4y + 21 = 9

Subtracting 21 from both sides of the equation, we get:

4y = -12

Dividing both sides of the equation by 4, we get:

y = -3

Therefore, the solution for this equation is y = -3.

2. 7y - 4(3y+5) = 2 - 3(4y-9)

Expanding the brackets, we get:

7y - 12y - 20 = 2 - 12y + 27

Simplifying both sides of the equation, we get:

-5y - 20 = 29 - 12y

Adding 12y to both sides of the equation, we get:

7y - 20 = 29

Adding 20 to both sides of the equation, we get:

7y = 49

Dividing both sides of the equation by 7, we get:

y = 7

Therefore, the solution for this equation is y = 7.