Question

111,11:(20,45-0,92x)-3,2=51

Answer 1

111,11:(20,45-0,92x)=51+3,2
20,45-0,92x=111,11:54,2
20,45-0,92x=2,05
0,92x=20,45-2,05
0,92x=18,4
х=20

Answer 2

I'm assuming you want me to solve the equation:

111,11:(20,45-0,92x)-3,2=51

First, let's simplify the left-hand side by dealing with the division:

111.11 / (20.45 - 0.92x) - 3.2 = 51

Now, we can isolate the fraction by adding 3.2 to both sides:

111.11 / (20.45 - 0.92x) = 51 + 3.2

Simplifying the right-hand side:

111.11 / (20.45 - 0.92x) = 54.2

Now, we can cross-multiply:

111.11 = 54.2 * (20.45 - 0.92x)

Divide both sides by 54.2:

111.11 / 54.2 = 20.45 - 0.92x

Simplify:

2.0515 = 20.45 - 0.92x

Subtracting 20.45 from both sides:

-18.3985 = -0.92x

Finally, divide both sides by -0.92:

20 = x

Therefore, the solution to the equation is x = 20.