Question

F(x)=x^3-4x^2+5 и x=-1

Answer 1

F'(x)=3x^2-8x


f'(-1)=3*(-1)^2-8*(-1)=3+8=11

Answer 2

To evaluate F(x) at x=-1, we simply substitute -1 for x in the expression for F(x):

F(-1) = (-1)^3 - 4(-1)^2 + 5

Simplifying the terms:

F(-1) = -1 - 4 + 5

F(-1) = 0

Therefore, F(-1) = 0 when F(x) = x^3 - 4x^2 + 5 and x = -1.