Question

1/4(x^2+2x-7)-1/3(x^2+x-2)=1/12(2x-7-x^2)

Answer 1

1/4(x^2+2x-7)-1/3(x^2+x-2) = 1/12(2x-7-x^2) | *12

3x^2+6x-21 -4x^2-4x+8 -2x+7+x^2 = 0

-6=0 - неверно

Answer 2

To solve the equation, we need to simplify and isolate the variable x on one side.

First, let's simplify the left side of the equation:

1/4(x^2+2x-7)-1/3(x^2+x-2)

= 1/4x^2 + 1/2x - 7/4 - 1/3x^2 - 1/3x + 2/3

= (-1/12)x^2 + (1/6)x - 11/12

Now, let's simplify the right side of the equation:

1/12(2x-7-x^2)

= (-1/12)x^2 + (1/6)x - 7/12

Now we can substitute these simplified expressions back into the original equation:

(-1/12)x^2 + (1/6)x - 11/12 = (-1/12)x^2 + (1/6)x - 7/12

We can see that the x^2 terms cancel out, leaving:

-11/12 = -7/12

This equation is not true, since -11/12 is not equal to -7/12. Therefore, the original equation has no solution.