Question

5,6-3(2-0, 4x) =0, 4(4x+1)

Answer 1

5,6-6+1,2х=1,6х+0,4
-0,4+1,2х=1,6х+0,4
1,2х-1,6х=0,4+0,4
-0,4х=0,8
х=-2

Answer 2

5,6-6+1,2x=1,6x+0,4
5,6-6-0,4=1,6x-1,2x
0,4x=-0,8
x=-0,8/0,4
x=-2

Answer 3

To solve the equation 5,6-3(2-0, 4x) = 0, 4(4x+1), let's simplify and solve step by step.

First, let's simplify the expression on both sides of the equation:

On the left side: 5,6 - 3(2 - 0,4x) becomes 5,6 - 6 + 1,2x (using the distributive property) Simplifying further, we have 5,6 - 6 + 1,2x = -0,4 + 1,2x

On the right side: 0,4(4x + 1) becomes 1,6x + 0,4 (using the distributive property)

Now, our equation becomes: -0,4 + 1,2x = 1,6x + 0,4

Let's isolate the variables on one side of the equation and the constants on the other side:

-0,4 - 0,4 = 1,6x - 1,2x + 0,4

-0,8 = 0,4x + 0,4

Next, let's isolate the variable by subtracting 0,4 from both sides of the equation:

-0,8 - 0,4 = 0,4x

-1,2 = 0,4x

Finally, divide both sides by 0,4 to solve for x:

-1,2 / 0,4 = x

x = -3

Therefore, the solution to the equation 5,6-3(2-0, 4x) = 0, 4(4x+1) is x = -3.