Question

Через точку О перетину діагоналей прямокутника ABCD проведено перпендикуляр К до площини АВС Знайдіть градусну міру кута АКО якщо АС=КС=10 см

Answer 1

Ав=Вс-Ас=СД
2+3-4= Сд
Сд-?
Сд=Ав+ас
Сд=2+4=6
Сд=6

Answer 2

Finding the Angle AKO in a Rectangle ABCD

To find the angle AKO in a rectangle ABCD, where AC = KC = 10 cm, we need to consider the properties of rectangles and the relationship between the diagonals and perpendiculars.

In a rectangle, the diagonals are equal in length and bisect each other. This means that the diagonal AC is equal in length to the diagonal BD, and they intersect at their midpoint.

Since AC = KC = 10 cm, we can conclude that the diagonal AC is divided into two equal segments: AK and KC. Therefore, AK = KC = 10 cm.

Now, let's consider the perpendicular line K drawn from the intersection of the diagonals to the plane ABC. Since K is perpendicular to the plane ABC, it forms a right angle with any line in the plane ABC that intersects it.

Therefore, the angle AKO is a right angle, measuring 90 degrees.

Please let me know if you have any further questions!