Question

Из вершины В тупого угла паралледограма ABCM проведены две различные высоты. Выполните рисунок и найдите отношение площадей отсекаемых или треугольников, если длины смежных сторон параллелограма равны 7 см и 4 см

Answer 1

Решение.....................

Answer 2

Solving for the Ratio of Areas in a Parallelogram

To solve for the ratio of areas of the triangles formed by the two different altitudes drawn from the vertex of a obtuse-angled parallelogram ABCM, we can follow these steps:

1. Draw the Parallelogram and Altitudes: - Start by drawing the parallelogram ABCM with an obtuse angle at vertex B. - Draw two different altitudes from vertex B to the opposite sides of the parallelogram.

2. Calculate the Areas of the Triangles: - Use the given lengths of the adjacent sides of the parallelogram, which are 7 cm and 4 cm, to calculate the areas of the triangles formed by the altitudes.

3. Find the Ratio of the Areas: - Once the areas of the triangles are calculated, find the ratio of the areas of the two triangles.

Let's proceed with the calculations.

Calculation

Given: - Length of one adjacent side of the parallelogram = 7 cm - Length of the other adjacent side of the parallelogram = 4 cm

We can use the formula for the area of a triangle, which is 1/2 * base * height, to calculate the areas of the triangles formed by the altitudes.

Let's assume the lengths of the altitudes are h1 and h2, and the bases of the triangles are 7 cm and 4 cm.

The area of the first triangle = 1/2 * 7 * h1 The area of the second triangle = 1/2 * 4 * h2

To find the ratio of the areas, we can divide the area of the first triangle by the area of the second triangle:

Ratio of Areas = (1/2 * 7 * h1) / (1/2 * 4 * h2) Ratio of Areas = (7 * h1) / (4 * h2)

This ratio will give us the relationship between the areas of the two triangles formed by the altitudes drawn from the obtuse-angled vertex of the parallelogram.

Conclusion

By following the steps outlined above, we can calculate the ratio of the areas of the triangles formed by the altitudes drawn from the vertex of the obtuse-angled parallelogram ABCM.