Question

В ромбе abcd угол abc равен 140 градусов найдите углы треугольника aob (O-точка пересечения диагоналей) СРОЧНО!!!!!

Answer 1

Привет! Угол авс=140,значит ушло овс= 140\2=70! Угол вос равен 90 по свуйству ромба! Значит вас = 180-90-70= 20. По теореме о сумме углов треугольника! Удачи

Answer 2

Finding the Angles of Triangle AOB

To find the angles of triangle AOB, where O is the point of intersection of the diagonals of rhombus ABCD, we can use the information that angle ABC in rhombus ABCD is 140 degrees.

Given: - Angle ABC in rhombus ABCD = 140 degrees

We know that the diagonals of a rhombus bisect each other at right angles, so angle AOB is a right angle, which is 90 degrees.

Now, to find the other angles of triangle AOB, we can use the fact that the sum of the angles in a triangle is 180 degrees.

Let's denote: - Angle A = AOB - Angle B = ABO

Using the fact that the sum of the angles in a triangle is 180 degrees, we can find the value of angle A and angle B.

Calculating the Angles

Using the given information and the fact that the sum of the angles in a triangle is 180 degrees, we can calculate the angles A and B.

We know: - Angle AOB = 90 degrees (as it is a right angle)

Now, we can use the fact that the sum of the angles in a triangle is 180 degrees to find the other angles.

Let's calculate: - Angle A - Angle B

Using the given information, we can calculate the angles A and B as follows:

- Angle A = 180 - 90 - 140 - Angle B = 180 - 90 - 140

Calculations

- Angle A = 180 - 90 - 140 = 50 degrees - Angle B = 180 - 90 - 140 = 50 degrees

So, the angles of triangle AOB are: - Angle A = 50 degrees - Angle B = 50 degrees

Therefore, the angles of triangle AOB, formed by the intersection of the diagonals of rhombus ABCD, are: - Angle A = 50 degrees - Angle B = 50 degrees - Angle AOB = 90 degrees