Question

Знайти кути рівнобедреного трикутника, якщо кут при вершині га 18° більший від кута при основі

Answer 1

Нехай кути при основі х°, тоді кут при вершині х+18°.
Маємо рівняння: х+х+х+18=180
3х=162
х=54
Кути при основі по 54°, кут при вершині 54+18=72°.

Answer 2

Finding the Angles of an Isosceles Triangle

To find the angles of an isosceles triangle when the angle at the vertex is 18° greater than the angle at the base, we can use the following approach:

1. Let's denote the angle at the base of the triangle as x. 2. Since the angle at the vertex is 18° greater than the angle at the base, the angle at the vertex can be represented as x + 18. 3. In an isosceles triangle, the base angles are equal, so we have: x = x.

Now, we can solve for the angles of the isosceles triangle.

Calculating the Angles

Using the information above, we can set up the equation: x + x + (x + 18) = 180 Solving for x: 3x + 18 = 180 3x = 162 x = 54

So, the angles of the isosceles triangle are: - x = 54° - x = 54° - x + 18 = 72°

Therefore, the angles of the isosceles triangle are 54°, 54°, and 72°.

This information is based on the principles of geometry and the properties of isosceles triangles.

Feel free to ask if you have any further questions or need additional assistance!