Question

Составьте уравнение прямой проходящей через точки A(4;-1) и B (2;-4) Через y=kx+b

Answer 1

Подставляем координаты в уравнение прямой и решаем систему из двух уравнений:
-1=k*4 + b
-4=k*2 +b
4k+b=-1
2k+b=-4
из первого уравнения вычтем второе:
2k=3
k=3/2
подставим в любое ур-е и найдем b:
b=-4 - 2*(3/2) = -7
Получаем ур-е прямой, проходящей через точки:
y=3/2 x -7

Answer 2

I can help you with your math question. To find the equation of a line that passes through two points, you need to find the slope and the y-intercept. The slope is the ratio of the change in y to the change in x. The y-intercept is the value of y when x is zero. Here are the steps to solve your problem:

- Find the slope of the line using the formula $$k=\frac{y_2-y_1}{x_2-x_1}$$ - Substitute the coordinates of the points A(4;-1) and B(2;-4) into the formula and simplify. You should get $$k=\frac{3}{2}$$ - Use the slope and one of the points to find the y-intercept using the formula $$y=kx+b$$ - Substitute the values of k, x, and y into the formula and solve for b. You can use either point, but I will use A(4;-1). You should get $$b=-7$$ - Write the equation of the line using the slope and the y-intercept. The final answer is $$y=\frac{3}{2}x-7$$

I hope this helps you understand how to find the equation of a line. If you have any other questions, feel free to ask me.Ответь+подробно.+Составьте+уравнение+прямой+проходящей+через+точки+A(4;-1)+и+B+(2;-4)++Через+y=kx+b