Question

Точка o центр окружности на которой лежат точки a b и c. известно что угол abc=15 градусов и угол aob=8 градусов найдите угол bco ответ дайте в градусах

Answer 1

уголАВС-вписанный=1/2дуги АС, дуга АС=уголАВС*2=15*2=30, уголАОВ-центральный=дуге АВ=8, из точки С проводим диаметр СК, уголВСО(ВСК)-вписанный=1/2дуги ВК, дуга ВК=дуга САВК-дуга АС-дуга АВ=180-30-8=142, уголВСО=142/2=71

Answer 2

Solution:

Given: - Points A, B, and C lie on a circle. - Angle ABC = 15 degrees. - Angle AOB = 8 degrees.

To find: - Angle BCO in degrees.

Calculating Angle BCO:

From the given information, we can use the properties of angles in a circle to find the measure of angle BCO.

First, we can find the measure of angle AOC using the fact that the angle at the center of a circle is twice the angle at the circumference subtended by the same arc.

Angle AOC = 2 * Angle ABC = 2 * 15 = 30 degrees.

Next, we can find the measure of angle BCO using the fact that the angle at the center of a circle is twice the angle at the circumference subtended by the same arc.

Angle BCO = 1/2 * Angle AOC = 1/2 * 30 = 15 degrees.

Therefore, the measure of angle BCO is 15 degrees.