Question

Отрезки MN и KP пересекаются в точке D, угол KMD= угол DNP, MD=DN. Докажите, что: а) треугольники KMD и DNP равны; б) угол MKD= угол NPD Помогите плз!

Answer 1

Никол , я очень сожалею , тоже не могу решить(

Объяснение:

Answer 2

#### Given Information: We are given the following information: - Line segments MN and KP intersect at point D. - Angle KMD is equal to angle DNP. - Segment MD is equal to segment DN. #### Proof: a) To prove that triangles KMD and DNP are equal, we can use the Side-Angle-Side (SAS) congruence criterion. According to this criterion, if two sides and the included angle of one triangle are equal to the corresponding sides and angle of another triangle, then the triangles are congruent. In this case, we have: - Side MD is equal to side DN. - Angle KMD is equal to angle DNP. - Side KM is common to both triangles. Therefore, we can conclude that triangles KMD and DNP are congruent by the SAS criterion. b) To prove that angle MKD is equal to angle NPD, we can use the Corresponding Angles Postulate. According to this postulate, if two lines are cut by a transversal, and the corresponding angles are congruent, then the lines are parallel. In this case, we have: - Angle KMD is equal to angle DNP (given). - Line segments MN and KP intersect at point D. Therefore, we can conclude that angle MKD is equal to angle NPD by the Corresponding Angles Postulate. Thus, we have proved both parts of the given statement. Please let me know if you need any further assistance!