Question

дано: ДМ-СРЕДНЯЯ ЛИНИЯ ТРЕУГОЛЬНИКА АБС периметр равен 68см АС-АБ=14 см БС-АБ =12 см.Найти ДМ.

Answer 1

АС=x=14,

АВ=x,

ВС=12=x, Составим уровнения

х+14+х+12+х=68

Зх+ 26=68

Зх=42

х=14

Значит Средняя линия треугольника 14см

 

 

 

 

Answer 2

Task: Find the length of the median DM in triangle ABC.

To find the length of the median DM in triangle ABC, we can use the formula for the length of a median in a triangle, which states that the length of a median from vertex A to side BC is half the length of side BC. We are given the perimeter of the triangle and the lengths of segments AS, BS, and AB.

Given Information:

- Perimeter of the triangle ABC = 68 cm - Length of AS = 14 cm - Length of BS = 12 cm

Solution:

1. First, let's find the length of side BC. We know that the perimeter of a triangle is the sum of the lengths of its three sides. Therefore, we can express the perimeter in terms of the lengths of the sides of triangle ABC: - Perimeter = AB + BC + AC - 68 = AB + BC + AC

2. Next, we can use the given information to find the length of side BC. We know that AS = AB, and BS = BC. Therefore, we can express AB and BC in terms of AS and BS: - AB = AS = 14 cm - BC = BS = 12 cm

3. Substituting the values of AB and BC into the perimeter equation, we get: - 68 = 14 + 12 + AC - 68 = 26 + AC - AC = 68 - 26 - AC = 42 cm

4. Now that we have found the length of side AC, we can use the median formula to find the length of the median DM. The median DM is half the length of side AC: - DM = 1/2 * AC - DM = 1/2 * 42 - DM = 21 cm

Therefore, the length of the median DM in triangle ABC is 21 cm.