Question

СРОЧНО!!!!! а) sin 140°= sin (180° - 40°) = ... 6) cos 126° = cos (180° - 54°) = ...; B) sin 85° = sin (90°-5°) = ...; r) cos 62° = cos (90° 28°) = ...​

Answer 1

Ответ: а) sin40°; б) -cos54°; в) cos5°; г) sin28°.​

Объяснение:

Нужно знать формулы приведения:

sin(180° - α) = sinα;       cos(180° - α) = - cosα;

sin(90° - α) = cosα;       cos(90° - α) = sinα.

Поэтому:

а) sin140°= sin(180° - 40°) = sin40°;

б) cos126° = cos(180° - 54°) = -cos54°;

в) sin85° = sin(90° - 5°) = cos5°;

г) cos62° = cos(90° - 28°) = sin28°.​

Answer 2

Certainly! Here are the trigonometric values you requested:

а)

1. $\sin(140^\circ) = \sin(180^\circ - 40^\circ) = \sin(40^\circ)$
2. $\cos(126^\circ) = \cos(180^\circ - 54^\circ) = \cos(54^\circ)$

b) 3. $\sin(85^\circ) = \sin(90^\circ - 5^\circ) = \cos(5^\circ)$

c) 4. $\cos(62^\circ) = \cos(90^\circ - 28^\circ) = \sin(28^\circ)$

Please note that these values are rounded to a reasonable number of decimal places. If you need more precise values, you might want to use a calculator.