Question

А=(0;-6) В=(-4;3) АВ-?

Answer 1

Ответ:  AB = √ 97 .

Объяснение:

А(0;-6) ;     В(-4;3) ;    АВ-?

AB = √[ (x₂ - x₁ )² + ( y₂ - y₁ )²] ;

AB = √[ (- 4 - 0 )²+ ( 3 + 6 )²] = √ ( 16 + 81 ) = √ 97 .

Answer 2

Ответ:

$\sqrt{97}$

Объяснение:

$A=(0,~-6)\\B=(-4,~3)$

Формула длины вектора по координатам:

$\displaystyle |\overrightarrow{AB}| = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

Подставим наши значения: $x_1=0,~~x_2=-4,~~y_1=-6,~~y_2=3$

$AB=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}=\sqrt{(0-(-4))^2+(-6-3)^2}=\sqrt{4^2+(-9)^2}=\\=\sqrt{16+81}=\sqrt{97}$

Answer 3

To find the distance between points A(0, -6) and B(-4, 3), you can use the distance formula, which is derived from the Pythagorean theorem.

The distance formula is given by:

$AB = \sqrt{(x2 - x1)^2 + (y2 - y1)^2}$

In this formula, (x1, y1) represents the coordinates of point A, and (x2, y2) represents the coordinates of point B.

Let's plug in the values:

A(0, -6) has coordinates (x1, y1) = (0, -6). B(-4, 3) has coordinates (x2, y2) = (-4, 3).

Now, plug these values into the distance formula:

$AB = \sqrt{(-4 - 0)^2 + (3 - (-6))^2}$ $AB = \sqrt{(-4)^2 + (3 + 6)^2}$ $AB = \sqrt{16 + 81}$ $AB = \sqrt{97}$

So, the distance between points A and B is √97, which is approximately 9.85 units.