Question

(4х-3)^2-25 Квадрат двочлена

Answer 1

Ответ:

(4x-3)²-25=16x²-24x+9-25=16x²-24x-16

Answer 2

To expand the square of the binomial $(4x - 3)^2$, you can use the formula $(a - b)^2 = a^2 - 2ab + b^2$. In this case, let $a = 4x$ and $b = 3$.

$(4x - 3)^2 = (4x)^2 - 2(4x)(3) + (3)^2$

Now, simplify the expression:

$= 16x^2 - 24x + 9$

Next, subtract 25:

$(4x - 3)^2 - 25 = 16x^2 - 24x + 9 - 25$

Combine like terms:

$= 16x^2 - 24x - 16$

So, $(4x - 3)^2 - 25$ simplifies to $16x^2 - 24x - 16$.