Question

2 cos² 135 + 6 sin 150 - 4 tg 0 cos 141

Answer 1

2(-sin(90+45))² + 6*sin(180-30) - 0 =     (tg0=0)

2*sin²45 + 6sin30=2*(√2/2)² + 6*(1/2)=

2*(2/4) + 3=4.

Answer 2

Let's break down the expression step by step:

1. cos²(135 degrees): The cosine of 135 degrees is -√2/2. So, cos²(135) = (-√2/2)² = 2/4 = 1/2.

2. 6 * sin(150 degrees): The sine of 150 degrees is 1/2. So, 6 * sin(150) = 6 * (1/2) = 3.

3. -4 * tan(0 degrees) * cos(141 degrees): The tangent of 0 degrees is 0, and the cosine of 141 degrees is approximately -0.869. So, -4 * 0 * (-0.869) = 0.

Now, let's put it all together:

2 * cos²(135) + 6 * sin(150) - 4 * tan(0) * cos(141) = (2 * 1/2) + 3 + 0 = 1 + 3 = 4.

So, the value of the expression is 4.