Question

Промінь AK належить куту BAD. Знайдіть кути ВАК i DAK, якщо кут ВАК у 7 разів менший від кута DAKi BAD = 72°. ​

Answer 1

Ответ:

<ВАК=9°

<ДАК=63°

Объяснение:

<ДАК=7<ВАК

<ВАД =<ДАК+<ВАК=72°

7<ВАК+<ВАК=72°

<ВАК=72/8=9°

<ДАК=9*7=63°

Answer 2

Промінь AK належить куту BAD. Знайдемо кути ВАК і DAK, якщо кут ВАК у 7 разів менший від кута DAK, а BAD = 72°.

Finding the angle BAK

To find the angle BAK, we need to subtract the angle BAD from 180° since they are supplementary angles. Given that BAD = 72°, we have:

BAK = 180° - BAD BAK = 180° - 72° BAK = 108°

Therefore, the angle BAK is 108°.

Finding the angle DAK

We are given that the angle BAD is 72° and the angle BAK is 108°. To find the angle DAK, we need to subtract the sum of angles BAD and BAK from 180° since they form a straight line.

DAK = 180° - (BAD + BAK) DAK = 180° - (72° + 108°) DAK = 180° - 180° DAK = 0°

Therefore, the angle DAK is 0°.

To summarize: - Angle BAK is 108°. - Angle DAK is 0°.

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