Question

Одна з сторін прямокутника у 4 рази менша за другу, а його периметр дорівнює 70 см. Знайти сторони прямокутника​

Answer 1

Пусть a, b — стороны прямоугольника (смежные), тогда a = 4b.

Периметр — сумма длин всех сторон, периметр прямоугольника равна удвоенной сумме двух его (смежных) сторон, P = 2(a+b) = 2(4b+b) = 2×5b = 10b, P = 70см,

10b = 70

b = 70÷10 = 7см.

Так, a = 4b = 4×7 = 28см.

Ответ: стороны прямоугольника равны 7см и 28см

Answer 2

Problem Statement

We are given that one side of a rectangle is 4 times smaller than the other side, and the perimeter of the rectangle is 70 cm. We need to find the lengths of the sides of the rectangle.

Solution

Let's assume that the longer side of the rectangle is represented by the variable x. According to the problem statement, the other side is 4 times smaller, so we can represent it as x/4.

The perimeter of a rectangle is given by the formula: 2 * (length + width). In this case, the perimeter is given as 70 cm, so we can set up the equation:

2 * (x + x/4) = 70

Simplifying the equation, we get:

2 * (5x/4) = 70

Multiplying both sides by 4/5 to isolate x, we get:

x = (70 * 4) / 5

Evaluating the expression, we find:

x = 56

Therefore, the longer side of the rectangle is 56 cm, and the shorter side is 56/4 = 14 cm.

So, the lengths of the sides of the rectangle are 56 cm and 14 cm.

Answer

The lengths of the sides of the rectangle are 56 cm and 14 cm.