Question

АВСД ромб площадь ромба равна 702 а диоганли равны (3х+6)(6х+10) найдите догональ ромба

Answer 1

Ответ:

x1=(-66+$\sqrt{25308}$)/36

x2=(-66-$\sqrt{25308}$)/36

Объяснение:

Так как площадь ромба равна полу произведению его диагоналей

получаем  (3х+6)(6х+10)=1/2*702

(3х+6)(6х+10)=351

18x^2+36x+30x+60=351

18x^2+66x-291=0

можно воспользоваться особенной формулой дискриминанта но я воспользуюсь обычной что бы было понятно

D=4356+20952=25308

x1=(-66+$\sqrt{25308}$)/36

x2=(-66-$\sqrt{25308}$)/36

Answer 2

Відповідь: 12
Відповідь: 12

Answer 3

Calculating the Diagonal of a Rhombus

To find the diagonal of a rhombus when the area of the rhombus is 702 and the product of its diagonals is given by (3x + 6)(6x + 10), we can follow these steps:

1. Find the Area of the Rhombus: - The area of a rhombus can be calculated using the formula: Area = (d1 * d2) / 2, where d1 and d2 are the diagonals of the rhombus.

2. Solve for the Diagonals: - Use the given area to find the value of the product of the diagonals, and then solve for the individual diagonals.

3. Calculate the Diagonal: - Once the values of the diagonals are found, the length of the diagonal can be calculated using the Pythagorean theorem.

Let's proceed with these steps.

Finding the Area of the Rhombus

The area of a rhombus is given by the formula: Area = (d1 * d2) / 2, where d1 and d2 are the diagonals of the rhombus.

Solving for the Diagonals

The product of the diagonals is given by (3x + 6)(6x + 10). We can use this information to solve for the individual diagonals.

Calculating the Diagonal

Once the values of the diagonals are found, the length of the diagonal can be calculated using the Pythagorean theorem.

Let's proceed with these calculations.