Question

В треугольнике ABC стороны AB=BC<AC Начертите треугольник и сравнить углы ПЖ!!+ рисунок!!!

Answer 1

Ответ:

∠В = ∠С < ∠A.

∠A может быть тупым.

Объяснение:

АВ = АС, значит треугольник АВС равнобедренный с основанием ВС.

В равнобедренном треугольнике углы при основании равны, значит

∠В = ∠С.

Напротив большей стороны лежит больший угол.

Большая сторона ВС, значит ∠А - больший.

∠В = ∠С < ∠A

Значит ∠A может быть тупым.

Answer 2

Ответ:АВ=ВС<АС

Объяснение:значит чертим АВ<АС и ВС<АС

Answer 3

Triangle ABC

To answer your question, let's start by drawing triangle ABC. Since AB = BC and AC is less than both AB and BC, we can draw a triangle where AB and BC are equal in length, and AC is shorter. Here is a visual representation of triangle ABC:

     A
    / \
   /   \
  /     \
 B-------C

Comparing Angles

Now let's compare the angles in triangle ABC. Since we don't have specific angle measurements, we can only make general observations based on the given information.

In triangle ABC, we know that AB = BC and AC is shorter. This means that angle BAC (angle A) and angle BCA (angle C) will be acute angles, while angle ABC (angle B) will be an obtuse angle.

To summarize: - Angle A (angle BAC) is acute. - Angle B (angle ABC) is obtuse. - Angle C (angle BCA) is acute.

Please note that without specific angle measurements, we can only make general conclusions based on the given information. If you have any additional information or specific angle measurements, please let me know, and I'll be happy to provide a more detailed analysis.

I hope this helps! Let me know if you have any further questions.