Question

СРОЧНО НУЖНА ПОМОЩЬ! Задача 8.Через гіпотенузу AB прямокутного трикутника ABC проведено площину а. Відстань від точки С до площини а дорівнює бсм. Який кут утворює пряма ВС з площиною а. АВ-14см.a AC=5см? Задача 9. Ортогональною проекцією правильного трикутника на площину, що містить одну з його вершин, є рівнобедрений трикутник з бічною стороною 3√13см. Сторона правильного трикутника 12см. Обчислити кут мiж площинами цих трикутників.

Answer 1

Ответ:

cpoчно помощь...

Объяснение:

хорошо хорошо

Answer 2

Task 8: Finding the Angle Formed by Line BC and Plane a in Right Triangle ABC

To solve this problem, we can use the principles of geometry and trigonometry to find the angle formed by line BC and plane a in right triangle ABC.

Given: - Hypotenuse AB of right triangle ABC - Plane a intersects the hypotenuse AB at point C - Distance from point C to plane a is equal to bsm - Length of AB is 14 cm - Length of AC is 5 cm

First, let's find the length of BC using the Pythagorean theorem: The Pythagorean theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

Using the Pythagorean theorem: BC = √(AB^2 - AC^2) BC = √(14^2 - 5^2) BC = √(196 - 25) BC = √171 BC ≈ 13.07 cm

Now, we can find the sine of the angle formed by line BC and plane a: sin(θ) = opposite/hypotenuse sin(θ) = bsm/BC sin(θ) = bsm/13.07

Given that the distance from point C to plane a is equal to bsm, we can find the sine of the angle θ.

Let's calculate the value of the sine of the angle θ using the given distance bsm.

Task 9: Calculating the Angle Between the Planes of Two Triangles

In this task, we are given a regular triangle and its orthogonal projection onto a plane containing one of its vertices. We need to find the angle between the planes of these two triangles.

Given: - Side length of the regular triangle = 12 cm - Orthogonal projection forms an isosceles triangle with a side length of 3√13 cm

To find the angle between the planes of these two triangles, we can use the properties of orthogonal projections and trigonometry.

The angle between the planes of the two triangles can be found using the following formula: cos(θ) = (a^2 + b^2 - c^2) / (2ab) where a, b, and c are the side lengths of the triangles.

We can use this formula to calculate the angle θ between the planes of the two triangles.

Let's calculate the angle θ using the given side lengths of the triangles.