Question

Дано трикутник ABC AB=BC=5 B=90°знайти площу трикутника АВС ​

Answer 1

Объяснение:

S=1/2×BC×AB=1/2×5×5=12,5 cм^2

Answer 2

I can help you with your math question. You want to find the area of a right triangle ABC, where AB = BC = 5 and B = 90°. The area of a right triangle is equal to half the product of the lengths of the legs, which are the sides adjacent to the right angle. In this case, the legs are AB and BC, so the area is:

$$S = \frac{1}{2} \cdot AB \cdot BC$$

Substituting the given values, we get:

$$S = \frac{1}{2} \cdot 5 \cdot 5$$

Simplifying, we get:

$$S = 12.5$$

Therefore, the area of the triangle ABC is 12.5 square units. You can learn more about the area of a right triangle from [this website](https://ua.onlinemschool.com/math/assistance/figures_area/triangle/). I hope this helps.