Question

Найти массу железа, которую можно получить с помощью алюминия из четырех кг оксида железа (III) содержащего 7 % примесей.

Answer 1

На листок не уместилось, так что отсылаю две фотки xD.

Answer 2

Calculation of Iron Mass Obtained from Aluminum

To calculate the mass of iron that can be obtained from four kilograms of iron(III) oxide (Fe2O3) containing 7% impurities, we need to consider the stoichiometry of the reaction between aluminum (Al) and iron(III) oxide.

The balanced chemical equation for the reaction is as follows:

2 Al + Fe2O3 -> 2 Fe + Al2O3

From the equation, we can see that two moles of aluminum react with one mole of iron(III) oxide to produce two moles of iron and one mole of aluminum oxide.

To find the mass of iron obtained, we need to determine the number of moles of iron(III) oxide present in four kilograms. We can then use the stoichiometry of the reaction to calculate the mass of iron produced.

Step 1: Calculate the Moles of Iron(III) Oxide

The molar mass of iron(III) oxide (Fe2O3) can be calculated by summing the atomic masses of its constituent elements:

Fe: 55.845 g/mol O: 16.00 g/mol (x3)

Molar mass of Fe2O3 = (2 x 55.845) + (3 x 16.00) = 159.69 g/mol

To find the number of moles of iron(III) oxide, we can use the formula:

moles = mass / molar mass

Given that the mass of iron(III) oxide is four kilograms (4000 grams), we can calculate the number of moles:

moles of Fe2O3 = 4000 g / 159.69 g/mol

Step 2: Calculate the Moles of Iron

From the balanced chemical equation, we know that two moles of aluminum react with one mole of iron(III) oxide to produce two moles of iron.

Therefore, the number of moles of iron produced is equal to half the number of moles of iron(III) oxide:

moles of Fe = (1/2) x moles of Fe2O3

Step 3: Calculate the Mass of Iron

To calculate the mass of iron obtained, we can use the formula:

mass = moles x molar mass

The molar mass of iron is 55.845 g/mol.

mass of Fe = moles of Fe x molar mass of Fe

Now, let's calculate the mass of iron obtained.

Calculation:

1. Calculate the moles of iron(III) oxide: - Moles of Fe2O3 = 4000 g / 159.69 g/mol = 25.05 mol

2. Calculate the moles of iron: - Moles of Fe = (1/2) x 25.05 mol = 12.53 mol

3. Calculate the mass of iron: - Mass of Fe = 12.53 mol x 55.845 g/mol = 698.6 g

Therefore, the mass of iron that can be obtained from four kilograms of iron(III) oxide containing 7% impurities is approximately 698.6 grams.

Please note that the above calculation assumes complete conversion of iron(III) oxide to iron and does not take into account any losses during the reaction or impurities in the starting material.