
Укажите реакции которые являются окислительно-восстановительными и объясните почему :
А)Si+2Cl₂=SiCl₄ Б)P₂O₅+3H₂O=2H₃PO₄ В)CaO+CO₂=CaCO₃ Г)K₂SO₃+2HCl=2KCl+SO₂↑+H₂O

Ответы на вопрос

В остальных они не изменились, следовательно, они не ОВР
Ответ: А



Reactions and Explanations of Oxidation-Reduction Reactions:
A) Si + 2Cl₂ = SiCl₄: This reaction involves the oxidation of silicon (Si) and the reduction of chlorine (Cl₂). Silicon is oxidized from an oxidation state of 0 to +4, while chlorine is reduced from an oxidation state of 0 to -1. The oxidation state of an element refers to the charge it would have if all the shared electrons were assigned to the more electronegative atom. In this case, silicon gains electrons and chlorine loses electrons.
B) P₂O₅ + 3H₂O = 2H₃PO₄: This reaction involves the oxidation of phosphorus (P₂O₅) and the reduction of water (H₂O). Phosphorus is oxidized from an oxidation state of +5 to +5 in H₃PO₄, while water is reduced from an oxidation state of 0 to +1 in H₃PO₄. The oxidation state of an element refers to the charge it would have if all the shared electrons were assigned to the more electronegative atom. In this case, phosphorus gains electrons and water loses electrons.
C) CaO + CO₂ = CaCO₃: This reaction involves the oxidation of carbon (CO₂) and the reduction of calcium oxide (CaO). Carbon is oxidized from an oxidation state of +4 to +4 in CaCO₃, while calcium is reduced from an oxidation state of +2 to +2 in CaCO₃. The oxidation state of an element refers to the charge it would have if all the shared electrons were assigned to the more electronegative atom. In this case, carbon gains electrons and calcium loses electrons.
Г) K₂SO₃ + 2HCl = 2KCl + SO₂↑ + H₂O: This reaction involves the oxidation of sulfite (SO₃²⁻) and the reduction of hydrogen chloride (HCl). Sulfite is oxidized from an oxidation state of +4 to +4 in SO₂, while hydrogen chloride is reduced from an oxidation state of 0 to -1 in KCl. The oxidation state of an element refers to the charge it would have if all the shared electrons were assigned to the more electronegative atom. In this case, sulfite gains electrons and hydrogen chloride loses electrons.
Please note that the explanations provided above are based on the oxidation states of the elements involved in the reactions.


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