Question

Какая масса оксида ртути разложилась, если получили 10 г. кислорода?

Answer 1

Х г 10 г
2 Hg2O. -> 4Hg. + O2
n=2моль n=1моль
М= 416 г/моль М=32 г/моль
m=832 г m=32 г

Х г Hg2O. - 10 г O2
832 г Hg2O. - 32 г О2
m(Hg2O)=832 * 10 / 32 = 260 г

Answer 2

Calculating the Mass of Mercury Oxide Decomposed

To calculate the mass of mercury oxide decomposed when 10g of oxygen is obtained, we can use the stoichiometry of the reaction. The balanced chemical equation for the decomposition of mercury oxide is:

2HgO → 2Hg + O2

From the balanced equation, we can see that 2 moles of mercury oxide decompose to produce 1 mole of oxygen. We can use this information to calculate the mass of mercury oxide decomposed.

Calculation

Given: - Mass of oxygen obtained (mO2) = 10g

Using the molar mass of oxygen (O2) which is approximately 32g/mol, we can calculate the moles of oxygen obtained: ``` moles of O2 = mass of O2 / molar mass of O2 = 10g / 32g/mol ≈ 0.3125 moles ```

Since 2 moles of mercury oxide decompose to produce 1 mole of oxygen, the moles of mercury oxide decomposed can be calculated as: ``` moles of HgO = 2 * moles of O2 = 2 * 0.3125 = 0.625 moles ```

Finally, we can calculate the mass of mercury oxide decomposed using the molar mass of mercury oxide (HgO), which is approximately 216.59g/mol: ``` mass of HgO decomposed = moles of HgO * molar mass of HgO = 0.625 moles * 216.59g/mol ≈ 135.37g ```

Conclusion

The mass of mercury oxide decomposed to produce 10g of oxygen is approximately 135.37 grams.