Question

Найдите массовую долю в полученного при смешивание 10г 2% расстворе и 40% 12 % раствора

Answer 1

Ответ:

1. m(в-ва)=m(р-ра)*w=120*0.4=48 (г)

2. m(в-ва)=180*0,1=18

3. w (конеч.)=m(в-ва)/m(р-ра)=48+18/120+180=0,22 или 22 %

Ответ: 22 %

(Можно еще решать по методу стаканчика, получим):

120*40+180*10=300х

4800+1800=300х

6600=300х

х=22 %

Answer 2

Calculating the Mass Fraction of the Mixture

To find the mass fraction of the resulting mixture, we can use the following formula:

Mass Fraction = (Mass of Component / Total Mass of Mixture) * 100%

Given: - 10g of 2% solution - 40g of 12% solution

Let's calculate the mass fraction of each component in the resulting mixture.

1. Mass Fraction of 2% Solution: - Mass of 2% solution = 10g - Total mass of mixture = 10g + 40g = 50g - Mass Fraction of 2% solution = (10g / 50g) * 100% = 20%

2. Mass Fraction of 12% Solution: - Mass of 12% solution = 40g - Total mass of mixture = 10g + 40g = 50g - Mass Fraction of 12% solution = (40g / 50g) * 100% = 80%

Therefore, the mass fraction of the resulting mixture is: - 20% for the 2% solution - 80% for the 12% solution

This means that the resulting mixture consists of 20% of the 2% solution and 80% of the 12% solution.