
Обчислити масу силікатної кислоти, яку можна одержати із натрій силікату масою 50 гi розчину
хлоридної кислоти масою 77 гз масовою часткою HCI25%?

Ответы на вопрос

розв'язок на фото внизу




To calculate the mass of silicic acid that can be obtained from sodium silicate and a solution of hydrochloric acid, we need to use the balanced chemical equation for the reaction between sodium silicate (Na2SiO3) and hydrochloric acid (HCl).
The balanced chemical equation for the reaction is:
Na2SiO3 + 2HCl → H2SiO3 + 2NaCl
From the equation, we can see that 1 mole of sodium silicate reacts with 2 moles of hydrochloric acid to produce 1 mole of silicic acid and 2 moles of sodium chloride.
To calculate the mass of silicic acid, we need to determine the number of moles of hydrochloric acid used. We can use the mass and molar mass of hydrochloric acid to calculate the number of moles.
Given: - Mass of sodium silicate solution (Na2SiO3) = 50 g - Mass of hydrochloric acid (HCl) = 77 g - Mass fraction of HCl in the solution = 25%
To find the mass of hydrochloric acid in the solution, we can use the mass fraction:
Mass of HCl = Mass of solution * Mass fraction of HCl Mass of HCl = 77 g * 0.25 = 19.25 g
Next, we can calculate the number of moles of hydrochloric acid:
Number of moles of HCl = Mass of HCl / Molar mass of HCl
The molar mass of hydrochloric acid (HCl) is approximately 36.5 g/mol.
Number of moles of HCl = 19.25 g / 36.5 g/mol ≈ 0.528 moles
According to the balanced chemical equation, 1 mole of sodium silicate reacts with 2 moles of hydrochloric acid to produce 1 mole of silicic acid. Therefore, the number of moles of silicic acid produced is also 0.528 moles.
To calculate the mass of silicic acid, we can use the molar mass of silicic acid. The molar mass of silicic acid (H2SiO3) is approximately 78 g/mol.
Mass of silicic acid = Number of moles of silicic acid * Molar mass of silicic acid Mass of silicic acid = 0.528 moles * 78 g/mol ≈ 41.184 g
Therefore, the mass of silicic acid that can be obtained from the given quantities of sodium silicate and hydrochloric acid is approximately 41.184 grams.
Please note that the above calculations assume ideal conditions and complete reaction conversion. In practice, the actual yield may be lower due to various factors such as side reactions, incomplete conversion, and losses during the process.


Похожие вопросы
Топ вопросов за вчера в категории Химия
Последние заданные вопросы в категории Химия
-
Математика
-
Литература
-
Алгебра
-
Русский язык
-
Геометрия
-
Английский язык
-
Химия
-
Физика
-
Биология
-
Другие предметы
-
История
-
Обществознание
-
Окружающий мир
-
География
-
Українська мова
-
Информатика
-
Українська література
-
Қазақ тiлi
-
Экономика
-
Музыка
-
Право
-
Беларуская мова
-
Французский язык
-
Немецкий язык
-
МХК
-
ОБЖ
-
Психология
-
Физкультура и спорт
-
Астрономия
-
Кыргыз тили
-
Оʻzbek tili