Question

Допишіть рівняння реакцій, розтавте кофіціенти: 1) Cu(OH)2+ HCl- 2)K2O+ P2O5- 3)KOH+ CO2-

Answer 1

Cu(OH)2 + 2HCl -> CuCl2 + 2H2O
3K2O + P2O5 -> 2K3PO4
2KOH + CO2 -> K2CO3 + H2O

Answer 2

1) Cu(OH)2 + 2HCl -> CuCl2 + 2H2O 2) 4K2O + P2O5 -> 2K4P2O7 3) 2KOH + CO2 -> K2CO3 + H2O

Here are the balanced chemical equations for the given reactions:

1) Cu(OH)2 + 2HCl -> CuCl2 + 2H2O - Copper(II) hydroxide (Cu(OH)2) reacts with hydrochloric acid (HCl) to form copper(II) chloride (CuCl2) and water (H2O).

2) 4K2O + P2O5 -> 2K4P2O7 - Potassium oxide (K2O) reacts with diphosphorus pentoxide (P2O5) to form potassium pyrophosphate (K4P2O7).

3) 2KOH + CO2 -> K2CO3 + H2O - Potassium hydroxide (KOH) reacts with carbon dioxide (CO2) to form potassium carbonate (K2CO3) and water (H2O).

Please note that these balanced equations are based on the information provided and may vary depending on the reaction conditions.