Question

NA2SO3<-H2SO3<-SO2<-S->SO3->K2SO4->BASO4

Answer 1

S+O2=SO2
SO2+H2O=H2SO3
H2SO3+2NaOH=Na2SO3+2H2O

2S+3O2=2SO3
SO3+2KOH=K2SO4+H2O
K2SO4+BaCl2=BaSO4+2KCl

Answer 2

The expression you've provided appears to represent a series of chemical reactions involving various sulfur-containing compounds. Let's break down each step:

1. Sulfite Ion (SO3^2-) reacts with water (H2O) to form Bisulfite Ion (HSO3^-): NA2SO3 (Sodium Sulfite) + H2O -> H2SO3 (Sulfurous Acid) -> SO2 (Sulfur Dioxide) + H2O The Sulfurous Acid (H2SO3) can further dissociate to produce the Sulfite Ion (SO3^2-).

2. Sulfur Dioxide (SO2) is a gas that can dissolve in water to form Sulfurous Acid (H2SO3): SO2 + H2O -> H2SO3

3. Sulfurous Acid (H2SO3) can lose a proton (H+) to form the Sulfite Ion (SO3^2-): H2SO3 -> SO3^2- + 2H+

4. The Sulfite Ion (SO3^2-) can react with Potassium Ion (K+) to form Potassium Sulfate (K2SO4): SO3^2- + 2K+ -> K2SO4 (Potassium Sulfate)

5. Barium Sulfate (BaSO4) can be formed by reacting Barium Ion (Ba^2+) with Sulfate Ion (SO4^2-): Ba^2+ + SO4^2- -> BaSO4 (Barium Sulfate)

So, it seems like you've provided a sequence of reactions that involve the transformation of sulfur-containing compounds, ultimately leading to the formation of Potassium Sulfate (K2SO4) and Barium Sulfate (BaSO4) from Sodium Sulfite (Na2SO3) and other intermediate species. If you have any specific questions or need further clarification about these reactions, please feel free to ask.