Question

В 15 моль C2H2 сколько литров, грамм, сколько число молекул

Answer 1

Відповідь:

M(C2H2)=26г/моль

m(C2H2)=15*26=390г

V(C2H2)=15*22,4=336л

N(C2H2)= 15*6,02*10²³=90,3моль⁻¹

Пояснення:

Answer 2

To calculate the volume, mass, and the number of molecules of 15 moles of C2H2 (acetylene), we'll use the following steps:

Step 1: Find the molar mass of C2H2. Step 2: Calculate the mass of 15 moles of C2H2. Step 3: Calculate the volume of 15 moles of an ideal gas at standard conditions (STP). Step 4: Calculate the number of molecules in 15 moles of C2H2.

Step 1: Molar Mass of C2H2 The molar mass of C2H2 (acetylene) is the sum of the molar masses of two carbon atoms (C) and two hydrogen atoms (H).

Molar mass of C = 12.01 g/mol Molar mass of H = 1.01 g/mol

Molar mass of C2H2 = 2 * molar mass of C + 2 * molar mass of H Molar mass of C2H2 = 2 * 12.01 g/mol + 2 * 1.01 g/mol Molar mass of C2H2 = 24.02 g/mol + 2.02 g/mol Molar mass of C2H2 = 26.04 g/mol

Step 2: Mass of 15 Moles of C2H2 Mass = Number of moles * Molar mass Mass = 15 mol * 26.04 g/mol Mass ≈ 390.6 g

Step 3: Volume of 15 Moles of C2H2 at STP At standard conditions (STP: 0°C or 273.15 K and 1 atm or 101.3 kPa), 1 mole of any ideal gas occupies approximately 22.71 L.

Volume = Number of moles * Molar volume at STP Volume = 15 mol * 22.71 L/mol Volume ≈ 340.65 L

Step 4: Number of Molecules in 15 Moles of C2H2 Avogadro's number (NA) represents the number of atoms or molecules in one mole of a substance, which is approximately 6.022 x 10^23 particles/mol.

Number of molecules = Number of moles * Avogadro's number Number of molecules = 15 mol * (6.022 x 10^23 molecules/mol) Number of molecules ≈ 9.033 x 10^24 molecules

So, for 15 moles of C2H2:

• Volume ≈ 340.65 liters
• Mass ≈ 390.6 grams
• Number of molecules ≈ 9.033 x 10^24 molecules