Вопрос задан 11.07.2023 в 20:09. Предмет Химия. Спрашивает Хачатурян Кристина.

1.Mg→ Х→MgSО4 2. S →X → H2SО4 3. Ва →X→ Вa(OH)2 4.Ca →CaO→Ca(OH)2→CaSO4 5. S→SO2→SO3→H2SO4→BaSO4

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Отвечает Дунаева Виктория.

Ответ:3 Mg(OH)2 + 2 H3PO4 = Mg3(PO4)2 + 6 H2O

Ba(OH)2 + H2SO4 = BaSO4 + 2 H2O

Объяснение:

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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

It looks like you've provided a series of chemical reactions involving different elements and compounds. I can help you understand these reactions step by step:

  1. Mg → X → MgSO4: In the first reaction, magnesium (Mg) is reacting with something represented by "X" to form magnesium sulfate (MgSO4). The missing compound "X" could potentially be sulfuric acid (H2SO4), which would react with magnesium to form magnesium sulfate and release hydrogen gas (H2).

  2. S → X → H2SO4: In this reaction, sulfur (S) is reacting with something represented by "X" to eventually form sulfuric acid (H2SO4). The intermediate compound "X" could be sulfur dioxide (SO2), which can be further oxidized to form sulfur trioxide (SO3), and then react with water (H2O) to produce sulfuric acid (H2SO4).

  3. Ba → X → Ba(OH)2: In this reaction, barium (Ba) is reacting with something represented by "X" to form barium hydroxide (Ba(OH)2). The intermediate compound "X" could potentially be barium oxide (BaO), which reacts with water to form barium hydroxide.

  4. Ca → CaO → Ca(OH)2 → CaSO4: This series of reactions involves calcium (Ca) first reacting with oxygen to form calcium oxide (CaO), commonly known as quicklime. When water (H2O) is added to quicklime, it undergoes a vigorous exothermic reaction to produce calcium hydroxide (Ca(OH)2), also known as slaked lime. Finally, calcium hydroxide reacts with sulfuric acid (H2SO4) to form calcium sulfate (CaSO4).

  5. S → SO2 → SO3 → H2SO4 → BaSO4: This sequence represents the conversion of sulfur (S) into barium sulfate (BaSO4) via various steps. Sulfur is first oxidized to sulfur dioxide (SO2), then further oxidized to sulfur trioxide (SO3). Sulfur trioxide reacts with water to form sulfuric acid (H2SO4). Finally, sulfuric acid reacts with barium chloride (BaCl2) to produce insoluble barium sulfate (BaSO4), which precipitates out of the solution.

These reactions involve various chemical processes, including oxidation, reduction, acid-base reactions, and precipitation. It's important to note that these reactions are simplified representations and may not take into account specific reaction conditions or side reactions that might occur in a real-world scenario.

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