Question

2H²S + 30² = 2SO² + 2H²O + 1166 кдж​

Answer 1

Ответ:

11,2 л Х кДж

2H2S. + 3O2. -> 2SO2. + 2H2O. + 1166 кДж

n=2 моль

Vm=22,4 л/моль

V=44,8 л

11,2 л H2S. - Х кДж

44,8 л H2S. - 1166 кДж

Q = 11,2 * 1166 / 44,8 = 291,5 кДж

Answer 2

The chemical equation you provided seems to have some errors in the chemical formulas and the balancing of the equation. Let's correct it and balance the equation:

The balanced chemical equation for the reaction between hydrogen sulfide (H2S) and oxygen (O2) to form sulfur dioxide (SO2) and water (H2O) with the given energy change of 1166 kJ is:

$2H_2S + 3O_2 \rightarrow 2SO_2 + 2H_2O \quad \text{(with }\Delta H = -1166 \text{ kJ)}$

In this balanced equation, two moles of hydrogen sulfide react with three moles of oxygen to produce two moles of sulfur dioxide and two moles of water, accompanied by the release of 1166 kJ of energy.