Question

Методом электронно-ионного баланса подберите коэффициенты в уравнении реакции Cu2O+HNO3(разб)→Cu(NO3)2+NO+H2O коэффициенты должны быть минимально возможными натуральными числами. В ответе приведите коэффициент перед окислителем.​

Answer 1

Ответ:

перед окислителем коэффициент 6

Answer 2

Balancing the Reaction Equation using the Electron-Ion Method

To balance the reaction equation Cu2O + HNO3(разб) → Cu(NO3)2 + NO + H2O, we can use the electron-ion method. The goal is to balance the number of atoms on both sides of the equation by adjusting the coefficients of the reactants and products.

Here is the balanced equation with the coefficients:

Cu2O + 4HNO3(разб) → 2Cu(NO3)2 + 2NO + 2H2O

In this balanced equation, the coefficient in front of HNO3(разб) is 4, which represents the number of moles of HNO3(разб) needed to react with Cu2O.

Please note that the coefficients are the minimum possible natural numbers that balance the equation.

The coefficient in front of the oxidizing agent HNO3(разб) is 4.