Question

Срочно! Прямо сейчас нужно! Как будет меняться водородный показатель, если через 500 мл 0,1 М раствора соляной кислоты пропустить 2,24 л аммиака ?

Answer 1

Ответ:

Показатель pH увеличится с 1,301 до 11,12

Объяснение:

Первоначальный pH среды

pH(HCl)=-lg(0.5*0.1)=1.301

NH3+H2O=NH4OH

n(NH3)=n(NH4OH)

n(NH4OH)=(2,24/22,4)=0,1

HCl+NH4OH=NH4Cl + H2O

n(HCl)=0.5*0.1=0.05

n(NH4OH)=0.1-0.05=0,05

Cm(NH4OH)=0,05/0.5=0,1

pOH=-lg(0.1*1,79 · 10-5)^1/2=2.88

pH=14-2.88=11,12

Изменение объемами пренебрежено.

Answer 2

Calculation of Hydrogen Ion Concentration Change

To determine how the hydrogen ion concentration will change when 2.24 liters of ammonia is passed through 500 ml of 0.1 M hydrochloric acid solution, we need to consider the reaction between ammonia (NH3) and hydrochloric acid (HCl). The balanced chemical equation for this reaction is:

NH3 + HCl → NH4Cl

From the balanced equation, we can see that one molecule of ammonia reacts with one molecule of hydrochloric acid to form one molecule of ammonium chloride.

To calculate the change in hydrogen ion concentration, we need to compare the moles of hydrochloric acid and ammonia used in the reaction.

1. Calculate the moles of hydrochloric acid: - Volume of hydrochloric acid solution = 500 ml = 0.5 liters - Concentration of hydrochloric acid = 0.1 M - Moles of hydrochloric acid = concentration × volume = 0.1 M × 0.5 L = 0.05 moles.

2. Calculate the moles of ammonia: - Volume of ammonia = 2.24 liters - Since the concentration of ammonia is not provided, we cannot directly calculate the moles of ammonia without knowing its concentration.

Unfortunately, the concentration of ammonia is not provided in the question, so we cannot determine the exact change in hydrogen ion concentration without this information. The concentration of ammonia is required to calculate the moles of ammonia and, subsequently, the change in hydrogen ion concentration.

Please provide the concentration of the ammonia solution so that we can proceed with the calculation.