Question

Cu(oh)2+2ch3cooh------(ch3coo)2Cu+2h2o. 2ch3cooh+na2co3------ch3coona+h2o+co2. Разложите на ионы, плес

Answer 1

Сu(OH)2↓+2CH3COOH⇒(CH3COO)2Cu+2H2O
Cu(OH)2↓+2CH3COO⁻+2H⁺=2CH3COO⁻+Cu⁺²+2H2O
Cu(OH)2↓+2H⁺=Cu⁺²+2H2O
2CH3COOH+Na2CO3=2CH3COONa+CO2↑+H2O
2CH3COO⁻+2H⁺+2Na⁺+CO3⁻²=2CH3COO⁻+2Na⁺+H2O+CO2↑
2H⁺+CO3⁻²=CO2↑+H2O