Question

Как из NaBr получить I2?​

Answer 1

Ответ:

Na+Br=I2

Объяснение:

Answer 2

Obtaining Iodine (I2) from NaBr

To obtain iodine (I2) from sodium bromide (NaBr), a common method involves the reaction with a strong oxidizing agent, such as sulfuric acid (H2SO4) and manganese dioxide (MnO2). Here's the detailed process:

1. Reaction with Sulfuric Acid and Manganese Dioxide: - Sodium bromide (NaBr) can be reacted with sulfuric acid (H2SO4) and manganese dioxide (MnO2) to produce iodine (I2). - The chemical equation for this reaction is: ``` 2NaBr + 2H2SO4 + MnO2 → Na2SO4 + MnSO4 + 2H2O + Br2 ``` - This reaction results in the formation of bromine (Br2), which can then be further reacted to obtain iodine (I2) through a displacement reaction.

2. Displacement Reaction to Obtain Iodine (I2): - The bromine (Br2) obtained from the previous reaction can be further reacted with a source of iodide ions (I-) to displace the bromine and obtain iodine. - The chemical equation for this displacement reaction is: ``` Br2 + 2I- → 2Br- + I2 ``` - This reaction results in the formation of iodine (I2) from the bromine (Br2) and iodide ions (I-).

3. Overall Reaction: - The overall reaction for obtaining iodine (I2) from sodium bromide (NaBr) involves the initial reaction with sulfuric acid and manganese dioxide to produce bromine (Br2), followed by the displacement reaction to obtain iodine (I2).