Question

ТЕРМІНОВО..ДАЮ 30 БАЛІВ Цинк кількістю речовини 0,5 моль прореагував з киснем. Яка кількість речовини кисню витратилася? Згорів фосфор кількістю речовини 0,2 моль. Яка кількість речовини кисню витратилася? Якій масі це відповідає?

Answer 1

Задача 1

Дано:

n(Zn)= 0,5 моль

Найти:

n(O2)-?

Решение:

2Zn+O2=2ZnO

n(Zn)=n(O2)= 0,25 моль

Ответ: n(O2)= 0,25 моль

Задача 2

Дано:

n(P)= 0,2 моль

Найти:

n(O2)-?

m(O2)-?

Решение:

4P+5O2=2P2O5

n(P)=n(O2)= 0,25 моль

m(O)=n*M= 0,25 моль*32 г/моль= 8 г

M(O2)+ 16*2 =32 г/моль

Ответ: n(O2)= 0,25 моль; m(O2) = 8 г

Answer 2

Chemical Reaction Calculations

To find the amount of substance of oxygen that reacted with zinc and phosphorus, we can use the balanced chemical equations and the concept of stoichiometry.

1. Reaction of Zinc with Oxygen: Given: Amount of substance of zinc = 0.5 moles We can use the balanced chemical equation for the reaction between zinc and oxygen: \[ 2Zn + O_2 \rightarrow 2ZnO \] According to the balanced equation, 1 mole of \(O_2\) reacts with 2 moles of \(Zn\). Therefore, the amount of substance of oxygen reacted can be calculated as: \[ \text{Amount of substance of oxygen} = 0.5 \, \text{moles} \times \frac{1 \, \text{mole} \, O_2}{2 \, \text{moles} \, Zn} = 0.25 \, \text{moles} \, O_2 \]

2. Reaction of Phosphorus with Oxygen: Given: Amount of substance of phosphorus = 0.2 moles The balanced chemical equation for the reaction between phosphorus and oxygen is: \[ 4P + 5O_2 \rightarrow P_4O_{10} \] According to the balanced equation, 5 moles of \(O_2\) react with 4 moles of \(P\). Therefore, the amount of substance of oxygen reacted can be calculated as: \[ \text{Amount of substance of oxygen} = 0.2 \, \text{moles} \times \frac{5 \, \text{moles} \, O_2}{4 \, \text{moles} \, P} = 0.25 \, \text{moles} \, O_2 \]

Mass Calculation

To calculate the mass of oxygen that reacted in each case, we can use the molar mass of oxygen, which is approximately 16.00 g/mol.

1. Mass of Oxygen Reacted in Zinc Reaction: \[ \text{Mass of oxygen} = \text{Amount of substance} \times \text{Molar mass} = 0.25 \, \text{moles} \times 16.00 \, \text{g/mol} = 4.00 \, \text{g} \]

2. Mass of Oxygen Reacted in Phosphorus Reaction: \[ \text{Mass of oxygen} = \text{Amount of substance} \times \text{Molar mass} = 0.25 \, \text{moles} \times 16.00 \, \text{g/mol} = 4.00 \, \text{g} \]

Therefore, the mass of oxygen that reacted in both cases is 4.00 grams.