Question

M(CaC2)=310 гр найти:m Ca(OH)2

Answer 1

Могу ошибаться, но у меня так получилось

Answer 2

To find the mass of Ca(OH)2 formed from 310 g of CaC2, we need to determine the stoichiometry of the reaction between CaC2 and Ca(OH)2.

The balanced equation for the reaction is:

CaC2 + 2H2O -> Ca(OH)2 + C2H2

From the balanced equation, we can see that 1 mole of CaC2 reacts with 2 moles of water (H2O) to produce 1 mole of Ca(OH)2.

First, we need to calculate the number of moles of CaC2:

Molar mass of CaC2 = (1 * atomic mass of Ca) + (2 * atomic mass of C) = (1 * 40.08 g/mol) + (2 * 12.01 g/mol) = 40.08 g/mol + 24.02 g/mol = 64.10 g/mol

Number of moles of CaC2 = Mass of CaC2 / Molar mass of CaC2 = 310 g / 64.10 g/mol ≈ 4.83 mol

According to the stoichiometry of the reaction, 1 mole of CaC2 produces 1 mole of Ca(OH)2. Therefore, the number of moles of Ca(OH)2 formed is also 4.83 mol.

Now, we can calculate the mass of Ca(OH)2:

Molar mass of Ca(OH)2 = (1 * atomic mass of Ca) + (2 * atomic mass of O) + (2 * atomic mass of H) = (1 * 40.08 g/mol) + (2 * 16.00 g/mol) + (2 * 1.01 g/mol) = 40.08 g/mol + 32.00 g/mol + 2.02 g/mol = 74.10 g/mol

Mass of Ca(OH)2 = Number of moles of Ca(OH)2 * Molar mass of Ca(OH)2 = 4.83 mol * 74.10 g/mol ≈ 358.23 g

Therefore, the mass of Ca(OH)2 formed from 310 g of CaC2 is approximately 358.23 grams.