Question

Срочно!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

$1.1)\; \; f(x)=132\; \; ,\; \; F(x)=132x+C\\\\2)\; \; f(x)=x^{11}\; \; ,\; \; F(x)= \frac{x^{12}}{12}+C\\\\3)\; \; f(x)= \frac{1}{x^8} \; ,\; \; F(x)=\frac{x^{-7}}{-7}+C=-\frac{1}{7x^7}+C\\\\4)\; \; f(x)=-2x+6x^9-0,5\\\\F(x)=-x^2+6\cdot \frac{x^{10}}{10}-0,5x+C\\\\5)\; \; f(x)=\frac{2}{5}+cosx\; \; ,\; \; F(x)= \frac{2}{5}x-sinx+C\\\\6)\; \; f(x)=(\sqrt2-6x)^5\\\\F(x)=-\frac{1}{6}\cdot \frac{(\sqrt2-6x)^6}{6}+C\\\\7)\; \; f(x)=\frac{1}{cos^2(3x+\pi )} \; ,\; \; F(x)=\frac{1}{3}\cdot tg(3x+\pi)+C$

$2.1)\; \; f(x)=7-6x^2+12x^3\; ,\; \; M(2,-25)\\\\F(x)=7x-2x^3+3x^4+C\\\\F(2)=14-16+48+C=-25\; ,\; \; C=-71\\\\f(x)=7x-2x^3+3x^4-71\\\\2)\; \; f(x)=\frac{1}{sin^2x}\; \; ,\; \; M( \frac{3\pi }{4},-5)\\\\F(x)=-ctgx+C\\\\F(\frac{3\pi}{4})=-ctg \frac{3\pi }{4}=ctg\frac{\pi}{4}=1+C=-5\; \; ,\; \; C=-6\\\\F(x)=-ctgx-6$