Question

Задание во вложении решите, пожалуйста

Answer 1

 
 $(\frac{4}{b-4\sqrt{b}} - \frac{\sqrt[2]{b^3}}{b^2-16b} )*\frac{\sqrt{b}+4}{4\sqrt{b}+16-b} = \\ \frac{4(b+4\sqrt{b})-\sqrt[2]{b^3}}{b^2-16b} * \frac{\sqrt{b}+4}{4\sqrt{b}+16-b} =\\ \frac{4b+16\sqrt{b}-\sqrt[2]{b^3}}{b^2-16b} * \frac{\sqrt{b}+4}{4\sqrt{b}+16-b} =\\ \frac{\sqrt{b}(4\sqrt{b}+16-b)}{4\sqrt{b}+16-b} * \frac{\sqrt{b}+4}{b^2-16b} = \\ \frac{ b+4\sqrt{b} }{b^2-16b} = \frac{ 1 } { b - 4\sqrt{b}}$