Question

Прошу, помогите решить!

Answer 1

$\frac{64b^2+128b+64}{b} : (\frac{4}{b}+4)=\\ \frac{64(b^2+2b+1)}{b}:(\frac{4+4b}{b})=\\ \frac{64(b+1)^2}{b}*\frac{b}{ 4(1+b)}=\\ 16b+16 = 16*-\frac{15}{16}+16 = -15+16=1$

Answer 2

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