Question

1)tg (3pi/2-a)*sin(pi-a)+cos(pi+a)=2)tg (pi/2+a)+ctg(2pi-a)=3) tg(a-pi/2)-cos(2pi-a) / sin(-a)-1=ctg(pi+a)Помогите пожалуйста

Answer 1

1)tg (3pi/2-a)*sin(pi-a)+cos(pi+a)=ctga*sina-cosa=cosa-cosa=0
2)tg (pi/2+a)+ctg(2pi-a)=-ctga-ctga=-2ctga
3) tg(a-pi/2)-cos(2pi-a) / sin(-a)-1=-ctga+cosa/sina-1=-ctga+ctga-1=-1

Answer 2

Task 1: Solve the equation tg(a) + (3pi/2 - a) * sin(pi - a) + cos(pi + a) = 0

To solve the equation tg(a) + (3pi/2 - a) * sin(pi - a) + cos(pi + a) = 0, we can follow these steps:

1. Simplify the equation using trigonometric identities. 2. Solve for the variable 'a'.

Let's go through these steps:

1. Simplify the equation using trigonometric identities:

- We can use the identity sin(pi - a) = sin(a). - We can use the identity cos(pi + a) = -cos(a).

Applying these identities, the equation becomes:

tg(a) + (3pi/2 - a) * sin(a) + (-cos(a)) = 0

2. Solve for the variable 'a':

To solve this equation, we need to find the values of 'a' that satisfy the equation. Unfortunately, without additional information or constraints, it is not possible to find a specific solution for 'a'.

However, we can still analyze the equation and make some observations:

- The equation involves trigonometric functions (tg, sin, cos), which are periodic functions with a period of 2pi. - The equation is nonlinear and contains multiple terms, making it difficult to find an exact solution.

To find approximate solutions, we can use numerical methods or graphing tools. These methods can help us find values of 'a' that make the equation approximately equal to zero.

Please let me know if you would like further assistance with numerical methods or graphing tools to find approximate solutions for 'a'.

Note: The search results did not provide specific information about this equation. The solution process is based on trigonometric identities and general knowledge about solving equations involving trigonometric functions.