
Найдите координаты вершины параболы y=-(x+1)в квадрате -4 . Постройте график


Ответы на вопрос




Finding the Coordinates of the Vertex
To find the coordinates of the vertex of the parabola y = -(x + 1)^2 - 4, we can use the general form of a quadratic equation, which is y = ax^2 + bx + c. In this case, a = -1, b = -2, and c = -4.
The x-coordinate of the vertex can be found using the formula x = -b / (2a). Plugging in the values, we get:
x = -(-2) / (2 * -1) = 2 / -2 = -1.
To find the y-coordinate of the vertex, we substitute the x-coordinate (-1) into the equation y = -(x + 1)^2 - 4:
y = -(-1 + 1)^2 - 4 = -0^2 - 4 = -4.
Therefore, the coordinates of the vertex of the parabola y = -(x + 1)^2 - 4 are (-1, -4).
Graphing the Parabola
To graph the parabola y = -(x + 1)^2 - 4, we can plot a few points and sketch the curve.
Let's choose some x-values and calculate the corresponding y-values:
- When x = -3: y = -(-3 + 1)^2 - 4 = -(-2)^2 - 4 = -4 - 4 = -8. So, we have the point (-3, -8).
- When x = -2: y = -(-2 + 1)^2 - 4 = -(-1)^2 - 4 = -1 - 4 = -5. So, we have the point (-2, -5).
- When x = -1: y = -(-1 + 1)^2 - 4 = -0^2 - 4 = -4. So, we have the vertex (-1, -4).
- When x = 0: y = -(0 + 1)^2 - 4 = -1^2 - 4 = -1 - 4 = -5. So, we have the point (0, -5).
- When x = 1: y = -(1 + 1)^2 - 4 = -2^2 - 4 = -4 - 4 = -8. So, we have the point (1, -8).
- When x = 2: y = -(2 + 1)^2 - 4 = -3^2 - 4 = -9 - 4 = -13. So, we have the point (2, -13).
Now, we can plot these points on a graph and sketch the curve of the parabola. The graph should have a downward-opening shape, with the vertex at (-1, -4).

Please note that the graph is a rough sketch and may not be perfectly accurate.


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