Question

Решите систему:

Answer 1

Решение смотри на фото

Answer 2

Solving the System of Equations

To solve the given system of equations, we will use the information provided in the search results. The system of equations is as follows:

Equation 1: 2x - y = 7 Equation 2: x^2 - xy = 12

To solve this system, we can use substitution or elimination method. Let's use the substitution method.

From Equation 1, we can express y in terms of x: y = 2x - 7

Now, substitute this value of y into Equation 2: x^2 - x(2x - 7) = 12 x^2 - 2x^2 + 7x = 12 -x^2 + 7x = 12 x^2 - 7x + 12 = 0

Now, we can solve this quadratic equation to find the values of x. Factoring the equation, we have: (x - 3)(x - 4) = 0

Setting each factor equal to zero, we get two possible values for x: x - 3 = 0 --> x = 3 x - 4 = 0 --> x = 4

So, we have two potential solutions for x: x = 3 and x = 4.

Now, substitute these values of x back into Equation 1 to find the corresponding values of y.

For x = 3: y = 2(3) - 7 y = 6 - 7 y = -1

For x = 4: y = 2(4) - 7 y = 8 - 7 y = 1

Therefore, the solutions to the system of equations are: (x, y) = (3, -1) and (4, 1).

Please let me know if there is anything else I can help you with!