Question

Помогите пожайлуста я сломал ногу и сижу дома пропустил темы а мне дали тесты а я незнаю как делать, только по подробней распишите 1)сократите дробь 3x-6/3(x-2) 2)выполните действие a/a-b - b/a+b 3)упростите 6x^3/x-5 * 25-x^2/18x^2 помогите 3 примера решить пожайлуста

Answer 1

1)3х-6/3х-6=1
2)а/(а-b) - b/(a+b)
Находим наим. общий знаменатель:
а(a+b)-b(a-b)/a^2-b^2
Раскрываем скобки в числителе:
а^2+ab-ab+b^2/a^2-b^2
Ответ:
а^2+b^2/a^2-b^2
3) Ответ: -х(5+х)/3

Answer 2

А что это за верхний уголок в 3 примере?

Answer 3

Simplify the Fraction: (3x-6)/(3(x-2))

To simplify the fraction (3x-6)/(3(x-2)), we can start by factoring out the common factor of 3 in the numerator:

(3x-6)/(3(x-2)) = 3(x-2)/(3(x-2))

Next, we can cancel out the common factor of (x-2) in the numerator and denominator:

3(x-2)/(3(x-2)) = 1

Therefore, the simplified form of the fraction (3x-6)/(3(x-2)) is 1.

Perform the Operation: a/(a-b) - b/(a+b)

To perform the operation a/(a-b) - b/(a+b), we need to find a common denominator for the two fractions.

The common denominator is (a-b)(a+b).

Now, let's rewrite the fractions with the common denominator:

a/(a-b) - b/(a+b) = (a(a+b))/(a(a-b)) - b(a-b)/(a+b)(a-b)

Next, we can simplify the expression:

(a(a+b))/(a(a-b)) - b(a-b)/(a+b)(a-b) = (a^2 + ab - ab + b^2)/(a^2 - ab + ab - b^2)

Simplifying further:

(a^2 + ab - ab + b^2)/(a^2 - ab + ab - b^2) = (a^2 + b^2)/(a^2 - b^2)

Finally, we can factor the numerator and denominator:

(a^2 + b^2)/(a^2 - b^2) = 1

Therefore, the result of the operation a/(a-b) - b/(a+b) is 1.

Simplify the Expression: (6x^3/(x-5)) * (25-x^2)/(18x^2)

To simplify the expression (6x^3/(x-5)) * (25-x^2)/(18x^2), we can start by canceling out any common factors in the numerator and denominator.

Let's factor the expressions:

6x^3 = 2 * 3 * x * x * x 25 - x^2 = (5 + x)(5 - x) 18x^2 = 2 * 3 * 3 * x * x

Now, let's simplify the expression:

(6x^3/(x-5)) * (25-x^2)/(18x^2) = (2 * 3 * x * x * x/(x-5)) * ((5 + x)(5 - x)/(2 * 3 * 3 * x * x))

Next, we can cancel out the common factors:

(2 * 3 * x * x * x/(x-5)) * ((5 + x)(5 - x)/(2 * 3 * 3 * x * x)) = (x/(x-5)) * ((5 + x)(5 - x)/(3 * x))

Simplifying further:

(x/(x-5)) * ((5 + x)(5 - x)/(3 * x)) = (x/(x-5)) * ((25 - x^2)/(3 * x))

Finally, we can cancel out the common factor of x:

(x/(x-5)) * ((25 - x^2)/(3 * x)) = (1/(x-5)) * ((25 - x^2)/3)

Therefore, the simplified form of the expression (6x^3/(x-5)) * (25-x^2)/(18x^2) is (1/(x-5)) * ((25 - x^2)/3).

I hope this helps! Let me know if you have any further questions.