Question

Является ли решением системы неравенств ∫x²-y<0 ∫2y-3x>3 пара чисел:a)(-3;4);б)(2;5);в)(0;-2) покажите решение,пожалуйста

Answer 1

.(-3)^(-4)=1/81(не входит) дальше вычисление не имеет смысла
2.2^(-5)=1/32(не входит)
3.0^(-(-2))=0;(2*(-2))=-4(не входит)

Answer 2

Solution to the System of Inequalities

To determine whether the pair of numbers (-3, 4), (2, 5), or (0, -2) satisfies the system of inequalities ∫x²-y<0 and ∫2y-3x>3, we can evaluate each pair and see which one satisfies both inequalities.

Let's start by evaluating each pair of numbers.

1. For the pair (-3, 4): - ∫(-3)²-4 = 9-4 = 5 - ∫2*4-3*(-3) = 8+9 = 17 - Therefore, the pair (-3, 4) does not satisfy the system of inequalities.

2. For the pair (2, 5): - ∫2²-5 = 4-5 = -1 - ∫2*5-3*2 = 10-6 = 4 - Therefore, the pair (2, 5) does not satisfy the system of inequalities.

3. For the pair (0, -2): - ∫0²-(-2) = 0+2 = 2 - ∫2*(-2)-3*0 = -4 - Therefore, the pair (0, -2) does not satisfy the system of inequalities.

Based on the evaluations, none of the given pairs (-3, 4), (2, 5), or (0, -2) satisfy the system of inequalities ∫x²-y<0 and ∫2y-3x>3.

Therefore, the solution to the system of inequalities does not include any of the given pairs.

Feel free to ask if you have any further questions or need additional assistance!