Question

Решит систему: х^(2)-y^(2)=72 x+y=9

Answer 1

  x^2-(-x+9)^2=72  

         x^2-(x^2-18x+81)=72

         x^2-x^2+18x-81-72=0

          18x-153=0

          18x=153

           x=8.5                     

Answer 2

решение во вложении))))))))))))

Answer 3

I can help you solve the system of equations. The system is:

$$ \begin{cases} x^2 - y^2 = 72 \\ x + y = 9 \end{cases} $$

To solve it, we can use the substitution method. We can express $y$ in terms of $x$ from the second equation:

$$ y = 9 - x $$

Then we can substitute this into the first equation and get a quadratic equation in $x$:

$$ x^2 - (9 - x)^2 = 72 $$

Expanding and simplifying, we get:

$$ x^2 - 81 + 18x - x^2 = 72 $$

$$ 18x = 153 $$

$$ x = \frac{153}{18} = \frac{17}{2} $$

Now we can plug this value of $x$ into the second equation and get the corresponding value of $y$:

$$ y = 9 - \frac{17}{2} = \frac{1}{2} $$

So the solution of the system is $(x, y) = (\frac{17}{2}, \frac{1}{2})$. This is the only solution, since the quadratic equation had only one root. You can check that this solution satisfies both equations. I hope this helps.Ответь+подробно.+Решит+систему:+х^(2)-y^(2)=72+x+y=9