Question

Помогите найти F производную функции f(x),если f(x)=1/sin^2x F(-3П/4)= -1

Answer 1

Я не настолько умная

Answer 2

I can help you with your math problem. Here is the solution:

To find the derivative of F(x), we need to use the chain rule and the quotient rule. The chain rule says that if f(x) = g(h(x)), then f'(x) = g'(h(x)) * h'(x). The quotient rule says that if f(x) = u(x) / v(x), then f'(x) = (u'(x) * v(x) - u(x) * v'(x)) / v(x)^2.

In this case, we have f(x) = 1 / sin^2(x), so we can write f(x) = g(h(x)), where g(x) = 1 / x^2 and h(x) = sin(x). Then, using the chain rule, we get:

f'(x) = g'(h(x)) * h'(x) = (-2 / h(x)^3) * cos(x) = (-2 / sin^3(x)) * cos(x)

Now, to find F'(x), we need to add the derivative of the constant term, which is zero. So we have:

F'(x) = f'(x) + 0 = (-2 / sin^3(x)) * cos(x)

To find the value of F'(x) at x = -3П/4, we need to plug in the value of x into the expression. We get:

F'(-3П/4) = (-2 / sin^3(-3П/4)) * cos(-3П/4) = (-2 / (-1)^3) * (-1) = 2

Therefore, the answer is F'(-3П/4) = 2. I hope this helps.Ответь+подробно.+Помогите+найти+F+производную+функции+f(x),если+f(x)=1/sin^2x+F(-3П/4)=+-1